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Math for Calculating the Length of Edgebanding on a Roll
Question
Forum Responses
When rolled on the drum, this same cross-section will be pi*R^2 - pi*r^2 where R = outer radius =(D/2), and r = inner radius (=C/2) So we have L*T = pi{D^2/4 - C^2/4}
If that doesn't do it - here's another:
Number of layers = (Do-Di)/(2t) [total thickness/one layer]
So the length is
A small error in the thickness measurement can make a big difference. I would recommend measuring it not with a micrometer, but by measuring the outside diameter of a roll of known length and calculating t from this formula in reverse. That will ensure that the number you use reflects the way the material lies on the roll. But try both measurements to see how they compare."
From the original questioner: As I read your response I began to think logically and kind of bastardized your second option with a simplified version that actually worked pretty well. (I selected a small roll from our edgeband cabinet so I'd be able to check my answer). I was within 6" of actual. I simply determined a average circumference by adding the outside and the inside (D*Pi) and then divided by 2. Then I multiplied this average circumference dimension by the number of layers. To determine this, the difference between the outside radius and the inside radius, divided by the thicknes of 1 layer. Like I said I was 6" of the actual, on a roll containing 30' (+/-). Now undoubtedly this error would compound itself with longer rolls but as I found out later by running the numbers on your actual second option, as well as your first (after enlisting the help of our engineer) none of the answers were spot on. In fact out of all of them, mine was the closest. Anyway, regardless of the means, I have my answer and I appreciate your help.
From contributor U: Being one of somewhat less technical background than other responders (English Literature), I simply weigh a 12 inch piece of subject edgebanding and weigh it. I weigh the roll of banding and divide that weight by the weight of the 12" piece. This provides amount of feet left on the roll within 1/2 to 3/4 of a foot. The process requires a good scale, but we've purchased a couple of them to use in the inventory of fasteners, edgebanding, t-molding, etc.
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